Question

Aflati termenul necunoscut a din următoarea egalitate: 3×60-3×[(4×a×4:8+5):5+31]=6×7×5:7

Answer 1

120-3×[(2a+5)÷5+31]=30

3×[(2a+5)÷5+31]=90/÷3

(2a+5)÷5+31=30

(2a+5)÷5=1

2a+5=5

2a=0=>a=0

Sper că te-am ajutat!

Answer 2

3 × 60 - 3 × [ ( 4 × a × 4 : 8 + 5 ) : 5 + 31 ] = 6 × 7 × 5 : 7

180 - 3 × [ ( 4 × a × 4 : 8 + 5 ) : 5 + 31 ] = 42 × 5 : 7

180 - 3 × [ ( 4 × a × 4 : 8 + 5 ) : 5 + 31 ] = 210 : 7

180 - 3 × [ ( 4 × a × 4 : 8 + 5 ) : 5 + 31 ] = 30

3 × [ ( 4 × a × 4 : 8 + 5 ) : 5 + 31 ] = 180 - 30

3 × [ ( 4 × a × 4 : 8 + 5 ) : 5 + 31 ] = 150

( 4 × a × 4 : 8 + 5 ) : 5 + 31 = 150 : 3

( 4 × a × 4 : 8 + 5 ) : 5 + 31 = 50

( 4 × a × 4 : 8 + 5 ) : 5 = 50 - 31

( 4 × a × 4 : 8 + 5 ) : 5 = 19

4 × a × 4 : 8 + 5 = 19 × 5

4 × a × 4 : 8 + 5 = 95

4 × a × 4 : 8 = 95 - 5

4 × a × 4 : 8 = 90

4 × a × 4 = 90 × 8

4 × a × 4 = 720

4 × a = 720 : 4

4 × a = 180

a = 180 : 4

a = 45