Question

aflati termenul necunoscut
a) (m+1120):80=81. b)5+a-[2000:5-(1291-1091)]=40.
c) 2×[14+(5+x):6]:8-7=8​

Answer 1

2)

a) ( m + 1120 ) : 80 = 81

m + 1120 = 81 • 80

m + 1120 = 6480

m = 6480 - 1120

m = 5360

b) 5 + a - [ 2000 : 5 - ( 1291 - 1091 )] = 40

5 + a - [ 400 - 200 ] = 40

5 + a - 200 = 40

5 + a = 40 + 200

5 + a = 240

a = 240 - 5

a = 235

c) 2 • [ 14 + ( 5 + x ) : 6 ] : 8 - 7 = 8

2 • [ 14 + ( 5 + x ) : 6 ] : 8 = 8 + 7 = 15

2 • [ 14 + ( 5 + x ) : 6 ] = 15 • 8 = 120

14 + ( 5 + x ) : 6 = 120 : 2 = 60

5 + x = 60 - 14 = 46

x = 46 - 5

x = 41