Question

aflati toate numerele de trei cifre care impartite la 18 , 224 , 32 dau de fiecrae data restul 11 ? repedeeee ( 50 DE PUNCTEEEEE ) !!!!!!!!!!!!

Answer 1

x : 18 = a rest 11⇒ x=18a+11 ⇒x-11=18a
x : 24 = b rest 11⇒ x=24b+11 ⇒x-11=24b
x : 32 = c rest 11⇒ x=32c+11 ⇒x-11 = 32c
⇒ x-1 multiplu comun de 18, 24 si 32
18=2*3²
24=2³ *3
32=2⁵  ⇒  3² *2⁵=9*32=228
x-11 ∈{228, 576, 864} ⇒ x∈{239 , 587 , 875}