Question

Aflati toate numerele mai mici de 200 care impartite pe rand la 28, 21 si 12 dau de fiecare data restul 9. Va roog mult!!!

Answer 1

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Answer 2

d : 28 = c₁ rest 9 ⇒ d - 9 = 28 × c₁

d : 21 = c₂ rest 9 ⇒ d - 9 = 21 × c₂

d : 12 = c₃ rest 9 ⇒ d - 9 = 12 × c₃

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⇒ d - 9 = cmmmc al numerelor ( 28; 21 si 12 )

28 = 2²× 7

21 = 3 × 7

12 = 2² × 3

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cmmmc al numerelor ( 28; 21 si 12 ) = 2² × 3 × 7 = 84

d - 9 = 84 ⇒ d = 84 + 9 = 93 → deimpartitul < 200

d = 2 × 84 + 9 = 168 + 9 = 177 < 200

Verific:

93 : 28 = 3 rest 9

93 : 21 = 4 rest 9

93 : 12 = 7 rest 9

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177 : 28 = 6 rest 9

177 : 21 = 8 rest 9

177 : 12= 14 rest 9

Raspuns: 93 si 177 → numerele