Question

aflati toate numerele naturale care impartite la7 dau catul egal cu restul

Answer 1

Răspuns:

Explicație pas cu pas:

D : 7 = C rest R

C = R

Conform T.Î.R. => D = Î × C + R , R < Î

=> R < 7

R = { 0 , 1 , 2 , 3 , 4 , 5 , 6 }

_________________________

• Cazul 1 :

R = 0 => C = 0

D : 7 = 0 rest 0

D = 0 × 7 + 0

D = 0 + 0

◇ D = 0

• Cazul 2 :

R = 1 => C = 1

D : 7 = 1 rest 1

D = 1 × 7 + 1

D = 7 + 1

◇ D = 8

• Cazul 3 :

R = 2 => C = 2

D : 7 = 2 rest 2

D = 2 × 7 + 2

D = 14 + 2

◇ D = 16

• Cazul 4 :

R = 3 => C = 3

D : 7 = 3 rest 3

D = 3 × 7 + 3

D = 21 + 3

◇ D = 24

• Cazul 5 :

R = 4 => C = 4

D : 7 = 4 rest 4

D = 4 × 7 + 4

D = 28 + 4

◇ D = 32

• Cazul 6 :

R = 5 => C = 5

D : 7 = 5 rest 5

D = 5 × 7 + 5

D = 35 + 5

◇ D = 40

• Cazul 7 :

R = 6 => C = 6

D : 7 = 6 rest 6

D = 6 × 7 + 6

D = 42 + 6

◇ D = 48