Question

aflati toate numerele naturale de trei cifre care impartite cu 11 da 3 , si impartite cu 10 da 2 ajutorrrr

Answer 1

n=10k+2
n+8=10k+2=8=10k+10=10m

n=11p+3
n+8=11p+3+8=11p+11=11r
n+8 multiplu de 10 side 11, deci multimplu de 110 (10si11, consecitive,deci prime intre ele)

n+8=110... n=102
n+8=220...n=212
numerele n merg din 110 in110 suntde forma 110s-8
n∈{102;212;322;432;542;652;762.872;982}
grea!!!