Question

aflati toate numerele naturale mai mici de 300 impartite la 5 , 6 si 8 de fiecare data sa fie rest 1 si catul diferit de 0

Answer 1

n=5xc1+1=6xc2+1=8xc3+1

n-1=5xc1=6xc2=8xc3

n-1=M [5,6,8]=M 120

n-1={120,2x120,3x120…}

n-1={120,240,360…}

n={121,241,361..}

dar n<300

=> n={121, 241}