Question

Aflati trei numere naturale a , b , c , astfel incat a + 1 : ( b + $\frac{1}{c}$ ) = $\frac{31}{9}$

Answer 1

[tex] \frac{a+1}{b+ \frac{1}{c} } = \frac{31}{9} 9(a+1)=31(b+ 1:c) [/tex]

9a+9=(31bc+31):c
9ac + 9c - 31bc = 31
c(9a+ 9 -31b) = 1 * 31
c = 1
9a -31b + 9 = 31
9a - 31b = 31-9=22
a=31
2817 - 31b = 22
31b = 2817 - 22
b = 2795 : 31