Question

aflati trei numere naturale consecutive. , stiind ca media lor este 79

Answer 1

(a+a+1+a+2):3=79
(3a+3):3=79
3a+3=79*3
3a+3=237
3a=237-3
3a=234
a=234:3
a=78
b=78+1
b=79
c=78+2
c=80

Answer 2

$M _{a}= \frac{a+b+c}{3}=79=\ \textgreater \ a+b+c=79*3=237 \\ a+b+c=79*3 \\ b=a+1 \\ c=a+2 \\ a+a+1+a+2=79*3-3 \\ 3a+3=237-3 \\ 3a=234 \\ a=234:3 \\ a=78 \\ b=a+1 \\ b=78+1 \\ b=79 \\ c=a+2 \\ c=78+2 \\ c=80$