Question

Aflati trei numere naturale consecutive stiind ca suma lor este egala cu: a) 60; b) 108.

Answer 1

Fie n, n+1 si n+2-cele 3 nr. naturale consecutive.

a) n+n+1+n+2=60

3n+3=60

3n=60-3

3n=57

n=57/3

n=19

n+1=19+1=20

n+2=19+2=21

Nr. cautate sunt: 19, 20, 21.

Verificare: 19+20+21=60

60=60 (adevarat)

b) n+n+1+n+2=108

3n+3=108

3n=108-3

3n=105

n=105/3

n=35

n+1=35+1=36

n+2=35+2=37

Numerele cautate sunt: 35, 36, 37.

Verificare:

35+36+37=108

108=108 (adevarat)