Question

Aflati trei numere naturale pare comsecutive stiind ca suma lor este a) 54; b) 96; c)150; d) 228

Answer 1

n=nr. cautat
A) n+(n+2)+(n+4)=54
3n+6=54
3n=54-6
3n=48
n=48:4
n=12
n+2=14
n+4=16
Nr sunt: 12 ; 14 ; 16
B) n+(n+2)+(n+4)=96
3n+6=96
3n=96-6
3n=90
n=90:3
n=3
n+2=5
n+4=7
Nr sunt: 3 ; 5; 7
C) n+(n+2)+(n+4)=150
3n+6=150
3n=150-6
3n=144
n=144:3
n=48
n+2=50
n+4=52
Nr sunt: 48 ; 50; 52
D) n+(n+2)+(n+4)=228
3n+6=228
3n=228-6
3n=222
n=222:3
n=74
n+2=76
n+4=78
Nr sunt: 74 ; 76; 78
SPER CA TE-AM AJUTAT! :)