Question

Aflati trei numere naturale x,y si z,stiind ca :
x+y=56,
y+z=88
x+z=80.

Answer 1

2x+2y+2z=56+88+80
x+y+z=224:2
x+y+z=112
56+z=112
z=112-56
z=56
y+56=88
y=88-56
y=32
x+32=56
x=56-32
x=24