Question

aflati valoarea lui a:24+3{16+5[14+2(44÷a+6)-32]-24}-20=10​

Answer 1

Răspuns:  a = 11

Explicație pas cu pas:

24 + 3 × {16 + 5 × [14 + 2 × (44 : a+6) - 32] - 24 } - 20 = 10

​24 + 3 × {16 + 5 × [14 + 2 × (44 : a+6) - 32] - 24 } = 10 + 20

24 + 3 × {16 + 5 × [14 + 2 × (44 : a+6) - 32] - 24 } = 30

3 × {16 + 5 × [14 + 2 × (44 : a+6) - 32] - 24 } = 30 - 24

3 × {16 + 5 × [14 + 2 × (44 : a+6) - 32] - 24 } = 6

16 + 5 × [14 + 2 × (44 : a+6) - 32] - 24 = 6 : 3

16 + 5 × [14 + 2 × (44 : a+6) - 32] - 24 = 2

16 + 5 × [14 + 2 × (44 : a+6) - 32] = 2 + 24

16 + 5 × [14 + 2 × (44 : a+6) - 32] = 26

5 × [14 + 2 × (44 : a+6) - 32] = 26 - 16

14 + 2 × (44 : a+6) - 32 = 10 : 5

14 + 2 × (44 : a+6) = 2 + 32

2 × (44 : a+6) = 34 - 14

44 : a + 6 = 20 : 2

44 : a = 10 - 6

44 : a = 4

a = 44 : 4

a = 11 → numarul, aflat prin metoda mersului invers