Question

Aflati valoarea lui a din egalitate : 2×[5+8:(4:2)+(3+2×a):9]-4×(4-6:2)=16

Aflati termenul necunoscut din :55-(5+x:5)×5=5

Answer 1

2×[5+8:(4:2)+(3+2×a):9]-4×(4-6:2)=16
2x[5+8:2+(3+2xa):9]-4x(4-3) = 16
2x[5+4+(3+2xa):9]-4x1 = 16
2x[9+(3+2xa):9]-4 = 16
2x[9+(3+2xa):9] = 16+4
2x[9+(3+2xa):9] = 20
9+(3+2xa):9 = 20:2
9+(3+2xa):9 = 10
(3+2xa):9 = 10-9
(3+2xa):9 = 1
3+2xa = 1x9
3+2xa = 9
2xa = 9-3
2xa = 6
a = 6:2
a = 3

55-(5+x:5)x5=5
(5+x:5)x5 = 55-5
(5+x:5)x5 = 50
5+x:5 = 50:5
5+x:5 = 10
x:5 = 10-5
x:5 = 5
x = 5x5
x = 25

Answer 2

2x[5+8:(4:2)+(3+2xa):9]-4x(4-6:2)=16
2x[5+8:2+(3+2xa):9]-4x(4-3)=16
2x[5+4+(3+2xa):9]-4x1=16
2x[9+(3+2xa):9]-4=16
2x[9+(3+2xa):9]=20
[9+(3+2xa):9]=20:2
[9+(3+2xa):9]=10
9+(3+2xa):9=10
9+(3+2xa)=9x10
9+(3+2xa)=90
3+2xa=90-9
3+2xa=81
2xa=81-3
2xa=78
a=78:2
a=39

55-(5+x:5)x5=5
55-(5+x:5)=5:5
55-(5+x:5)=1
5+x:5=55-1
5+x:5=54
x:5=54-5
x:5=49
x=49x5
x=245