Question

aflati valoarea lui a din egalitatea: [(3.a+19):5-2]11+2=35

Answer 1

[(3×a+19):5-2]11+2=35
[(3×a+19):5-2]11 = 35 - 2
[(3×a+19):5-2]11 = 33
(3×a+19):5-2 = 33 : 11
(3×a+19):5-2 = 3
(3×a+19):5 = 3+2
(3×a+19):5 = 5
3×a+19 = 5×5
3×a+19 = 25
3×a = 25-19
3×a = 6
a = 6:3
a = 2