Question

Aflati valoarea numarului natural ,,x" din egalitatile:
a) 3+3×[3+3×(3+3×X)]=120;
b) [(X×48)÷4+1]×5+15=500.
Apropo ixsul mic este ori iar cel mare este X

Answer 1

a) 3+3*[3+3*(3+3X)]=120
3+3*[3+9+9X]=120
3+3*12+27X=120
27X=120-3-36
27X=81
X=3
b)[ 48X/4+1]*5+15=500
[12X+1]*5+15=500
60X+5+15=500
60X=500-20
X=8

Answer 2

3+3×[3+3×(3+3×X)=120; 3×[3+3×(3+3×X)=117; 3+3×(3+3×X)=39; 3×(3+3×X)=36; 3+3×X=12; 3×X=9; X=3.