Question

Aflati valoarea parametrului real $\alpha$ pentru care ecuatia:2x-5x+a=0 nu are solutii

Answer 1

[tex]2x^2-5x+a=0\\ Pentru\ ca\ ecuatia\ sa\ nu\ aiba\ solutii\ \Delta\ trebuie\ sa\ fie\ mai\ mic\ ca\ 0.\\ \Delta\ \textless \ 0\\ 25-4\cdot2\cdot a\ \textless \ 0\\ 25-8a\ \textless \ 0\\ 25\ \textless \ 8a\\ a\ \textless \ \frac{25}{8} \Rightarrow a\in (\frac{25}{8},-infinit)[/tex]