Question

aflati valorea raportului algebric : x+y pe x² y² pentru x=√2-1 , y = √2+1

Answer 1

(x+y)/x²y²=2√2/1=2√2

x+y=√2-1+√2+1 = 2√2
x²=(√2-1)²=2+1-2√2=3-2√2
y²=(√2+1)²= 2+1+2√2=3+2√2
x²y²=(3-2√2)(3+2√2)=9-8=1

sau x²y²=(xy)²=[(√2-1)(√2-1)]²=(2-1)²=1²=1
{formula (a-b)(a+b)=a²-b²}