Question

aflati valorile lui a 50÷ {34 + 2 ×[10_2×( 6 a: 6)]} +3 =4 coronița te rog

Answer 1

50:{34+2x[10-2x(6a:6)]}+3=4
50:{34+2x[10-2x(6a:6)]}=4-3
50:{34+2x[10-2x(6a:6)]}=1
34+2x[10-2x(6a:6)]=1x50
34+2x[10-2x(6a:6)]=50
2x[10-2x(6a:6)]=50-34
2x[10-2x(6a:6)]=16
10-2x(6a:6)=16:2
10-2x(6a:6)=8
-2x(6a:6)=8-10
-2x(6a:6)=-2
6a:6=-2:(-2)
6a:6=1
6a=1x6
6a=6
a=6:6
a=1