Question

Aflati x:
c) 29-5(x+1)=4
d) 2(3x-1)=3(x+2)+4
e)[37-(x-1)•3]•2=14
f) [(x-3)•2+7]:5=15

Answer 1

c)
29-5x-5=4
24-5x=4
-5x=+4-24
-5x=-20
x=4
d)
6x-2=3x+6+4
6x-2=3x=10
6x-3x=10+2
3x=12
x=4
e)
(37-3x+3)*2=14
(40-3x)*2=14
80-6x=14
-6x=14-80
-6x=-66
x=11
f)
(2x-6+7):5=15
(2x+1) totul supra 5=15⇒amplifici cu 5 in ambele parti
2x+1=15*5
2x+1=75
2x=75-1
2x=74
x=74:2
x=37

Answer 2

d)
d)
c)

29-5(x+1)=4
29-5*(x+1)+4=0
(29-5*(x+1))-4=0
20-5x=-5*(x-4)
-5*(x-4)=0
-5=0
x-4=0
x=4

d)

2(3x-1)=3(x+2)+4
2*(3*x-1)-(3*(2+x)+4)=0
(2*(3x-1)-(3*(x+2)+4=0
2*(3x-1)-(3x+10)=0
3x-12=3*(x-4)
3*(x-4)=0
3=0
x-4=0
x=4 

e)

[37-(x-1)*3]*2=14
[37-(x-1)*3]*2-(14)=0
[37-3*(x-1)]*2-14=0
2*(40-3x)-14=0
66-6x=-6*(x-11)
-6*(x-11)=0
-6=0
x-11=0
x=11

f)

[(x-3)*2+7]:5=15
[(x-3)*2+7]/5-(15)=0
(2*(x-3)+7)/5 -15=0
2x+1/5=>(2x+1)/5-15=0
15=15/1=15*5/5
(2x+1)-(15*5)/5=2x-74/5
2x-74=2*(x-37)
2*(x-37)/5=0
2*(x-37_/5=0*5
2*(x-37)=0
2=0
x-37=0
x=37