Question

Aflati x din:
1)2*{120-2*[(2*x+18)/15+108]/11} egal cu 200.
2)2010^0+{2*[3+(x-2^2)*5]}/6*7 egal cu 2^3.
3)2*x+4*x+...4024*x egal cu 2012*2013.VA ROG DIN TOT SUFLETUL AJUTATIMa!!!!

Answer 1

1)2*{120-2*[(2*x+18)/15+108]/11} = 200
120-2*[(2*x+18)/15+108]/11 = 200:2
-2*[(2*x+18)/15+108]/11 = 100-120
(2*x+18)/15+108 = 20*11/2
(2*x+18)/15+108 = 110
(2*x+18)/15= 110-108
(2*x+18)= 2*15
2*x=30-18
2x=12
x=6


2)2010⁰+{2*[3+(x-2²)*5]}/6*7= 2³
{2*[3+(x-4)*5]}/6*7= 8-1
[2*(3+5x-20)]/6*7= 7
[2*(5x-17)]/6*7= 7
(10x-34)/6*7=7
10x-34=7/7*6
10x-34=6
10x=6+34
10x=40
x=4

3)2*x+4*x+...4024*x = 2012*2013
2x(1+2+...2012) = 2012*2013
2x2012(2012+1):2 = 2012*2013
x 2012*2013 = 2012*2013
x=1