Question

AFLATI X DIN:

2•{7•[10-3•(x+5)]-10}= -6

Answer 1

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Answer 2

2 · { 7 · [ 10 - 3 · ( x + 5 ) ] - 10 } = -  6

7 · [ 10 - 3 · ( x + 5 ) ] - 10 = (- 6) : 2

7 · [ 10 - 3 · ( x + 5 ) ] = ( - 3) + 10

10 - 3 ·  ( x + 5 ) = 7 : 7

3 · ( x + 5 ) = 10 - 1

3 ·  ( x + 5 ) = 9

x + 5 = 9 : 3

x + 5 = 3

x = 3 - 5

x = - 2  

Verific:

2 x { 7 x [ 10 - 3 x ( - 2 + 5 ) ] - 10 } = - 6

=  2 x [ 7 x ( 10 - 3 x 3 ) - 10 ] =

= 2 x ( 7 x 1 - 10 ) =

= 2 x ( - 3 ) =

= - 6