Question

Aflati x din egalitatea: 104-64:{13-12:[22-20:(38-4x)]+4}=100

Answer 1

104-64:{13-12:[22-20:(38-4x)]+4}=100
64:{13-12:[22-20:(38-4x)]+4}=104-100
64:{13-12:[22-20:(38-4x)]+4}=4
13-12:[22-20:(38-4x)]+4=64:4
13-12:[22-20:(38-4x)]+4=16
13-12:[22-20:(38-4x)]=16-4
13-12:[22-20:(38-4x)]=12
12:[22-20:(38-4x)]=13-12
12:[22-20:(38-4x)]=1
22-20:(38-4x)=12:1
22-20:(38-4x)=12
20:(38-4x)=22-12
20:(38-4x)=10
38-4x=20:10
38-4x=2
4x=38-2
4x=36
x=36:4
x=9