Question

Aflati x din egalitatea:(2013⁰+1+2+2²+2³+...+2¹⁰⁰)·x=2¹⁰¹.

Answer 1

2013 ^0. =1; 1+1=2; 2+. 2=4; 4+2^2=8=2^3; 2^3+ 2^3=16=2^4;.... La sf vom avea 2^100+2^100= 2^101; 2^101.x= 2^101; x=1