Question

Aflati x din egalitatea
[(6,12÷1,8-1,4x)×2,8-1,8²]×0,1=0,2²​

Answer 1

[(6,12÷1,8-1,4x)×2,8-1,8²]×0,1=0,2²

[(3.4-1.4x)×2,8- 3.24]×0.1= 0.04 /÷0.1

(3.4-1.4x)×2,8- 3.24=0.4

(3.4-1.4x)×2,8=3.64 /÷2.8

3.4-1.4x= 1.3

1.4x=3.4-1.3

1.4x=2.1

x= 2.1÷ 1.4

x=1.5

Answer 2

Răspuns:

1,8²=1,8·1,8

[(6,12÷1,8-1,4x)×2,8-1,8²]×0,1=0,2²

[(3,4-1,4x)×2,8-3,24]·0,1=0,04:0.1

(3,4-1,4x)·2,8=3,64:2,8

1,4x=3,4-1,3

x=2,1:1,4

x=1,5