Question

aflati x din proportia 0,(3)-1/3xtotul supra 1la puterea 1998+0,1(6)x=1/4

Answer 1

[0,(3)- 1/3 ×x]/[1¹⁹⁹⁸+0,1(6)x]=1/4
(1/3- 1/3 ×x)/(1+x/6)=1/4
[(1-x)/3]/[(6+x)/6]=1/4
(1-x)/3  × 6/(6+x)=1/4
2(1-x)/(6+x)=1/4
(2-2x)/(6+x)=1/4
8-8x=6+x
9x=2
x=2/9