Question

aflati x,y z IP cu 2;3;5si x+y+z=62​

Answer 1

Răspuns:

x = 30 ;  y = 20 ;  z = 12

Explicație pas cu pas:

x + y + z = 62

2x = 3y = 5z

x = 3y/2

z = 3y/5

⁵⁾3y/2 + ¹⁰⁾y + ²⁾3y/5 = ¹⁰⁾62 =>

15y + 10y + 6y = 620 =>

31y = 620 => y = 620:31 => y = 20

x = 3·20/2 = 3·10 => x = 30

z = 3·20/5 = 3·4 => z = 12

x + y + z = 30+20+12 = 62 , corect