Question

Aflati x y z stiind ca sunt direct proportonele cu nr 0,1 2 supra 5 si 1supra 3 si ac suma lor este 1

Answer 1

x=0,1k=k/10
y=2k/5
z=k/3
x+y+z=1
k/10+2k/5+k/3=1
3k+12k+10k=30
25k=30
k=30/25=6/5
x=k/10=(6/5)/10=6/50
y=2k/5=2*(6/5)/5=12/25
z=k/3=(6/5)/3=6/15=2/5

verificare
6/50+12/25+2/5=(6+12*2+2*10)/50=(6+24+20)/50=50/50=1