Question

Aflati zerourile functiei f:R-->R:
a) f(x)=16x la puterea a2 -4

Answer 1

[tex]f(x)=0\\ 16x^2-4=0\\ (4x)^2-2^2=0\\ (4x-2)(4x+2)=0\\ 4x-2=0=>x= \frac{2}{4} = \frac{1}{2} \\ 4x+2=0=>x=-\frac{2}{4} =- \frac{1}{2} [/tex]