Question

aflati3 nr. consecutive stiind ca suma lor este cu 37 mai mare decat nr. cel mic !!!!!! va rog ajutatima!!!!!

Answer 1

a+a+1+a+2=37+a
3a+3=37+a
3a-a+3=37
2a+3=37
2a=37-3
2a=34
a=34:2
a=17
b=17+1
b=18
c=17+2
c=19
proba:17+18+19=37+17
           35+19=37+17
            54=54

Answer 2

Fie nr. consecutive: n, n+1 si n+2

n+(n+1)+(n+2)=37+n
3n+3=37+n
2n=34
n=34:2
n=17
n+1=18
n+2=19

Succes!