Question

aflatin3 nr. xyz stiind ca x+y=56 y+z=88 si x+z =80

Answer 1

x+y+y+z+x+z=56+88+80
2(x+y+z)=224
x+y+z=224÷2=112
56+z=112
z=112-56=56
x+88=112
x=112-88=23
y+80=112
y=112-80=32