Question

aflaty x,y,z stiind ca sunt direct proportionale cu 4,6,8 si x/2+y/3+z/4=90

Answer 1

x/4=y/6=z/8=k
x=4k
y=6k
z=8k
4k/2+6k/3+8k/4=90
2k+2k+2k=90
6k=90
k=90÷6
k=15
x=4×15
x=60
y=6×15
y=90
z=8×15
z=120

Answer 2

x/4=y/6=z/8=k⇒x=4k⇒y=6k⇒z=8k

4k/2+6k/3+8k/4=90

2k+2k+2k=90

6k=90

k=15

x=4×15⇒x=60
y=6×15⇒y=90
z=8×15⇒z=120
ver
x/2+y/3+z/4=90⇒ 60÷2+90÷3+120÷4= 30+30+30=90