Question

Aflti numerele a, b si c stiind ca sint invrs proportionale cu numerele 3,8,si 12 si ca 4a+2b-3c=64

Answer 1

3a=8b=12c=n
a=n/3; b=n/8; c=n/12
Inlocuim
4n/3+2n/8+3n/12=64
16n/12+3n/12+3n/12=64
16n+3n+3n/12=64
22n=768
n=34,(90)
a=104,(72)
b=279,(27)
c=418,(90)