Question

ai
1. Află factorul necunoscut:
a x 3 = 27
(3 + 4) > a = 56
9 x a = 63
a x (25 - 17) = 72
a x 8 = 48
(100 - 91) x a = 36
7x a = 42
a x (4 + 5) = 45
5x a = 50 (1000 - 992) x a = 48
8xa = 8
a x (10 - 10) = 0
a x 5 x 5 = 25
2 x 4 xa = 40
a x 2 x 3 = 24
9 x 1 x a = 81
3xax2 = 54
axa x 8 = 32​

Answer 1

Răspuns:

1)a×3=27|÷3

a=27÷3=9→a=9

2)9<a=56

3)9×a=63|÷9

a=7

4)a×8=72|÷8

a=9

5)a×8=48|÷8

a=6

6)9×a=36|÷9

a=4

7)7×a=42|÷7

a=6

8)a×9=45|÷9

a=5

9)?

10)8×a=8|÷8

a=1

11)a×0=0→a=0

12)a×25=25|÷25

a=1

13)8×a=40|÷8

a=5

14)a×6=24|÷6

a=4

15)10×a=81

a=8,1

16)6×a=54|÷6

a=9

17)2a×8=32|÷8

2a=4|÷2

a=2