Question

Aici sunt primele 3 supuncte:
a)
$(x - \sqrt{3} ) {}^{2} - (2 \sqrt{3} ) {}^{2}$
b)
$( \sqrt{2} - y) {}^{2} - ( \sqrt{2} {)}^{2}$
c)
$( \sqrt{3} - 1) {}^{2} - 3$

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Answer 1

A) (x-\/3)^2- (2\/3)^2

X^2-2.x.\/3+\/3^2-4.\/9

X^2-2\/3x+\/9-4.3

X^2-2\/3x+3-12

X^2-2\/3x-9

B) (\/2-y)^2-(\/2)^2

(\/2)^2-2.y.\/2+y^2-\/4

\/4-2\/2y+y^2-2

2-2\/2y+y^2-2

= -2\/2y+y^2

C) (\/3-1)^2-3

(\/3)^2-2.\/3.1+1^2-3

\/9-2\/3+1-3

3-2\/3+1-3

= 1-2\/3

D) (2x+\/5)^2 - \/45

(2x)^2+2.2x.\/5+ \/5^2 - 3\/5

4x^2+4\/5x+5-3\/5

= 4x^2+\/5+5

E) 27x^2- (1-\/3x)^2

27x^2- (1^2-2.1.\/3+(\/3)^2

27x^2- 1+2\/3-3

27x^2+2\/3-4

F) (a+\/2b) ^2 - 8b^2

A^2+2\/ab+2b-8b^2

G) (x+\/7)^2- (2x+2\/7)^2

X^2+2\/7x+7-(4x^2+8\/7x+7)

X^2+2\/7x+7-4x^2-8^7-7

= -3^2-6\/7

H) 8x^2-(\/2x+1)^2

8x^2- (2x+2\/2x+1)

8x^2-2x-2\/2-1

I) (x+\/3)^4- (\/3)^4

X^4+4.x.\/3+(\/3)^4 - (\/3)^4

X^4+4\/3x+9-9

= x^4 + 4\/3x