Question

AJUTA-TI-MA dau Coronaaaaaaaaaaaa

Answer 1

Banuiesc ca 2-ul il vrei rezolvat.
a) Il scriem pe 8 si pe 4 ca puteri ale lui 2 si obtinem (2^9):(2^4)+2-1=(2^5)+2-1=32+2-1=33
b) [(7,35+24,5)+10(5,19+1,25)]:3,5=
(31,85+10*6,44):3,5=
(31,85+64,4):3,5=
96,25:3,5= 27,5
c) {[(125+75)*3+75-2*25]:25^2 +16 *39-5^3}:10^2=
[(200*3+75-50):25^2 + 624-5^3]:10^2=
(625:25^2 +624-5^3):10^2=
([25^2]:[25^2]+624-5^3):10^2=
(625-5^3):10^2=
(625-125)/100=
500/100 = 5