Question

Ajutamimă {[(a+2) x 2+2]x2+2} x2+2=30​

Answer 1

Răspuns:

{[(a+2) x 2+2]x2+2} x2+2=30​

{[(a+2) x 2+2]x2+2} x2=30​-2

[(a+2) x 2+2]x2+2=28:2

[(a+2)x2+2]x2=14-2

(a+2)x2+2=12:2

2a+4=6-2

2a=4-4

a=0

Answer 2

Răspuns:

Explicație pas cu pas:

{[(a+2) x 2+2]x2+2} x2+2=30  <=>

{[2a+4+2]x2+2} x2=30-2 = 28 <=>

{[2a+6]x2+2} = 28 :2 = 14  <=>

4a+12+2 = 14 <=> 4a = 14-14 => 4a = 0 => a = 0