Question

Ajutati-ma cat de repede se poate .
Rezolvati urmatoarele ecuati in multimea numerelor reale:

12x-1=4x-65
15x+4=12x+6
5(x-1)+7(x-2)=5
x+3(2x-1)=3x+21
2(x-1)=3(x+5)
3x=5(3x+2)+26
3(2x-1)+2(x-1)=0
4(2x-1)+5(x-1)=10(2x+4)
7(1-x)+6(2-3x)=3x=5(1-3x)
10(2x-5)+9(2x-3)+8(2x-1)=3(1-x)-2(3-3)+5(2-x)-32

Answer 1

12x-1=4x-65               15x+4=12x+6
12x-4x=1-65                15x-12x=6-4
8x=-64                        3x=3
x=-8                             x=1

Answer 2

12x-1=4x-65/- 4x
8x-1=-65/+1
8x=-64/:8
x=-8

15x+4=12x+6/-12x
3x+4=6/-4
3x=2/:3
x=2/3

5(x-1) +7(x-2)=5
5x-5+7x-14=5
12x-19=5/+19
12x=24/:12
x=2

x+3(2x-1)=3x+21
2x²-x+6x-3=3x+21
2x²+5x-3=3x+21/-2x²
5x-3=3x+21/-3x
2x-3=21/+3
2x=24/:2
x=12

2(x-1)=3(x+5)
2x-2=3x+15/-2x
-2=x+15/-15
-17=x

3x=5(3x+2)+26
3x=15x+10+26
3x=15x+36/-3x
0=12x+36/-36
-36=12x/:12
-3=x

3(2x-1)+2(x-1)=0
6x-3+2x-2=0
8x-5=0/+5
8x=5/:8
x=5/8

4(2x-1)+5(x-1)=10(2x+4)
8x-4+5x-5=20x+40
13x-9=20x+40/-13x
-9=7x+40/-40
-49=7x/:7
-7=x

7(1-x)+6(2-3x)=3x=5(1-3x)??

10(2x-5)+9(2x-3)+8(2x-1)=3(1-x)-2(3-3)+5(2-x)-32
20x-50+18x-27+16x-8=3-3x-6+6+10-5x-32
54x-69=19-8x/+8x
62x-69=19/+69
62x=88/:62
88/62=x
/ -linie de fractie