Question

Ajutati-ma cu acest exercitiu va rog.
Am distribuita la fizica maine.

Answer 1

[tex]\displaystyle \text{Se da:}\\ \\ m=11600kg\\ \\ R_p=6400km=6400000m\\ \\ M_p=6\times 10^{24}kg\\ \\ K=6,67\times 10^{-11}\frac{N\times m^2}{kg^2}\\ \\ a)h=0m,\text{ }F=?N\\ \\ b)h=600km=600000m,\text{ }F=?N\\ \\ \\[/tex]


[tex]\displaystyle\text{Formule:}\\ \\ \text{Forta o aflam din legea atractiei universale:}\\ \\ F=K\times\frac{m\times M_p}{r^2}\\ \\ \\ a)r=R_p\\ \\ F=K\times\frac{m\times M_p}{R_p^2}\\ \\ \\ b)r=R_p+h\\ \\ F=K\times\frac{m\times M_P}{(R_p+h)^2}\\ \\ \\[/tex]


[tex]\displaystyle \text{Calcule:}\\ \\ a)F=6,67\times 10^{-11}\times\frac{11600\times 6\times 10^{24}}{6400000^2}\approx 113338N\\ \\ b)F=6,67\times 10^{-11}\times\frac{11600\times 6\times 10^{24}}{(6400000+600000)^2}\approx 94741N\\ \\ [/tex]