Question

Ajutati-ma cu exercitiu: (5x-1)(5x+1)-(4x+3) totul la 2 +2(3x-1) totul la 2

Answer 1

$(5x-1)(5x+1)-(4x+3)^2+2(3x-1)^2= \\ =25x^2-1-[(4x)^2+2 \cdot 4x \cdot 3+3^2]+2[(3x)^2-2 \cdot 3x \cdot 1+1^2]= \\ =25x^2-1-(16x^2+24x+9)+2(9x^2-6x+1)= \\ =25x^2-1-16x^2-24x-9+18x^2-12x+2= 27x^2-36x-8$