Question

Ajutați-mă la cele două ex cu albastru pliz dau coroană

Answer 1

- se calculeaza masa molara

MH2O=2+ 16=18---------> 18g/moli

18g H2O-----------16g O

36g H2O---------------xg O

x-36.16 : 18=32 g O

MH2SO4=2+32+4.16=98------->98g/moli

mH2SO4= 2moli . 98g/moli=196 g

98g H2SO4 ---------64g O

196g------------------------y

y=196.64 :98=128 g O

0,15 kmoli=150moli SO2

M=32+ 2.16=64--------->64g/moli

64g SO2---------------32g O

150moli----------------------z

z=150.32 : 64=75 g O

g H2O

6g H

M=2+16=18-------->18g/moli

18 g H2O------------------2g H

xg-----------------------------6g H

x=18 .6 :  2=54 g H2O

g PH3

6g H

M=31 + 3=34--------> 34g/moli

34g-----------3g H

y g ---------------6gH

y=   calculeaza !!!!!!!!!!!!!!!!!!

gH2CO3

6gH

M=2+12 +3.16=62-------->62 g /moli

62g H2CO3--------------2g H

zg-----------------------------6gH

z=calculeaza !!!!!!!!!!!!