Question

Ajutati ma si pe mine va rog

Answer 1

Răspuns:

1.

a)

C₃² = 3!/(2!·1!) = 3·2!/2! = 3

P₃ = 3! = 3·2·1 = 6

C₃² + P₃ = 3+6 = 9

b)

C₅⁴ = 5!/(4!·1!) = 5·4!/4! = 5

A₅⁴ = 5!/1! = 5·4·3·2·1 = 120

C₅⁴ -A₅⁴ = 5-120 = -115

2.

a = C₄⁰ + P₂ = 4!/(0!·4!) + 2! = 1 + 2·1 = 3

b = C₃⁰ +A₅² = 3!/(0!·3!) + 5!/3! = 1 + 5·4·3!!/3! = 1 + 5·4 = 21

⇒ b > a