Question

Ajutati ma si pe minee

Answer 1

1)nd=0,25 moli NaOH

napa=9 moli H20

masa NaOH=40 g/mol

n=m/M=>m=n*M=0,25*40=10 g NaOH

n=m/M=>m=9*18=162 g H20

ms=md+mH20=162+10=172 g

C=md/ms*100

C=10/172*100

C=5,8%

2)md=10*240/100

md=24 g

mH20=ms-md

mH2O=240-24

mH2O=216 g

Baftă!