Question

ajutati.ma si pe mn la problema cu \/

Answer 1

[tex]\frac{x}{\sqrt{5}-2}=\frac{\sqrt{5}+2}{x}\\ Inmultim\ pe\ diagonala:\\ x^2=(\sqrt5-2)(\sqrt5+2)\\ x^2=5-4\\ x^2=1\\ |x|=1\\ De\ aici\ avem\ doua\ solutii:\\ x_1=1, x_2=-1\\ Dar:\ x\ \textless \ 0=\ \textgreater \ S:x=-1[/tex]