Question

Ajutați ma si pr mine va roggggg repede dau 30 de puncte

Answer 1

8.
a=unghi 1
a+20=unghi 2
(a+a+20)/2=62°
2a+20=124°
a+10=62°
a=52°
a+20=72°


9.
360=2³×3²×5   
nr de divizori  (3+1)(2+1)(1+1)=4×3×2=24
divizorii lui 360  sunt : 1,2,3,4,5,6,8,9,10,12,15,18,20,24,30,36,40,45,60,72,90,120,180,360,
alegem 3≤n≤10
nr de unghiuri n={3,4,5,6,8,9,10}

n=3
ma=(a+a+1+a+2)/3=360°/3=120°
n=4 
ma=(a+a+1+a+2+a+3)/4=360°/4=90°
n=5 
ma=(a+a+1+a+2+a+3+a+4)/5=360°/5=72°
n=6 
ma=(a+a+1+a+2+a+3+a+4+a+5)/6=360°/6=60°
n=8 
ma=(a+a+1+a+2+a+3+a+4+a+5+a+6+a+7)/8=360°/8=45°
n=9 
ma=(a+a+1+a+2+a+3+a+4+a+5+a+6+a+7+a+8)/9=360°/9=40°
n=10 
ma=(a+a+1+a+2+a+3+a+4+a+5a+6+a+7+a+8+a+9)/10=360°/10=36°