Question

Ajutati-ma su pe mine va rog la o problema!Exercitiul 4 si daca se poate si 5!

Answer 1

4)
A(m,0)∈Gf ⇒f(m)=0⇒ [tex] m^{2} +m-2=0\\ m^2+2m-m-2=0\\ m(m+2)-(m+2)=0\\ (m+2)(m-1)=0\\ m+2=0 \\ m=-2\\ m-1=0\\ m=1[/tex]
5)[tex]E(x)=\frac{2x+1}{x+1}+\frac{2x+2-x-1}{(x+1)(x+2)}\cdot\frac{(x+2)(x-2)}{x^2+3x-2x-6}\\ =\frac{2x+1}{x+1}+\frac{x+3}{x+1}\cdot \frac{x-2}{(x+3)(x-2)}=\\ \frac{2x+1}{x+1}+\frac{1}{x+1}=\frac{2x+2}{x+1}=\frac{2(x+1)}{x+1}=2[/tex]

Answer 2

vezi atasament ex 4 si 5
ex 4 sev putea face si cu x1,x2 cu Δ dar am preferat cudescompunere