Question

Ajutati-ma va dau coroana si puncte numai daca rezolvati urmatoarea inegalitate
${2}^{x} \times {3}^{x} \geqslant {36}^{x} \times \sqrt{6}$

Answer 1

6^x≥6^(2x+1/2)
dar
6>1
atunci
x≥2x+1/2
0≥x+1/2
-1/2≥x
x≤-1/2
x∈(-∞;-1/2]