Question

Ajutati-ma va rog !
1) (1+i)+(-3+2i)-(6i-3i)=
2) x*2+2x+3=0
3) (2i-5)x+3iy=-5-4i

Answer 1

1)
(1+i)+(-3+2i)-(6i-3i)=(1-3)+(i+2i-6i+3i)=-2+0i=-2.

2)
x*2+2x+3=0 <=> 4x+3=0 <=> x=-3/4.

3)
x,y apartin R.

(2i-5)x+3iy=-5-4i <=> -5x+(2x+3y)i=-5-4i <=> -5x=-5 si 2x+3y=-4 <=> x=1 si y=(-4-2x)/3 <=> x=1 si y=-2.