Question

Ajutati-ma Va Rog : 402+[1002:3-(100+a)x2]:14=408

Answer 1

402+[1002:3-(100+a)×2]:14=408
[1002:3-(100+a)×2]:14=408-402
[1002:3-(100+a)×2]:14=6
1002:3-(100+a)×2=6×14
1002:3-(100+a)×2=84
334-(100+a)×2=84
-(100+a)×2=-250
(-100-a)×2=-250
-200-2a=-250
-2a=-250+200
-2a=-50
a=-50:(-2)
a=25

Verificare:
402+[1002:3-(100+25)×2]:14=408


S-ar putea si asa dar tot acolo ajungi.
402+[1002:3-(100+a)×2]:14=408
[1002:3-(100+a)×2]:14=408-402
[1002:3-(100+a)×2]:14=6
1002:3-(100+a)×2=6×14
1002:3-(100+a)×2=84
334-(100+a)×2=84
334-(200+2a)=84
334-200-2a=84
134-2a=84
Cred ca pentru clasa a IV-a de aici e fara solutie.