Question

Ajutati-ma va rog !!!
a) 3,2x[2,6+4,25+3x(12,3+2,6\2)]-3,8\0=
b) 2,5\3:2,5\2+4,5x[12,8-0,5x(13,9-7,75)]=
c) 2,54+(1223,34\2-12,3\2)\0-1,08:2=
d) 3,5\2-1,2x{11+1,1x[6,5+2x(0,45-0,4)]}=
e) [0,8+4x(o,34x10+1,2:2)]:0,168=

Answer 1

a)3,2x[2,6+4,25+3x(12,3+2,6 la puterea 2)]-3,8 la puterea0=
=3,2x[2,6+4,25+3x(12,3+6,76)]-1=
=3,2x(2,6+4,25+3x19.06)-1=
=3,2x(2,6+4,25+57,18)-1=
=3,2x(6,85+57,18)-1=
=3,2x64,03-1=
=204,896-1=
=203,896
b) 2,5 la puterea 3:2,5 la puterea 2+4,5x[12,8-0,5x(13,9-7,75)]=
=2,5 la puterea 3-2+4,5x[12,8-0,5x(13,9-7,75)]=
=2,5+4,5x[12,8-0,5x(13,9-7,75)]=
=2,5+4,5x(12,8-0,5x6,15)=
=2,5+4,5x(12,8-3,075)=
=2,5+4,5x9,725=
=2,5+43,7625=
=46,2625
c) 2,54+(1223,34 la puterea 2-12,3 la puterea 2) la puterea 0-1,08:2=
=2,54+1-1,08:2=
=2,54+1-0,54=
=3,54-0,54=
=3
d) 3,5 la puterea 2-1,2x{11+1,1x[6,5+2x(0,45-0,4)]}=
=12,25-1,2x{11+1,1x[6,5+2x(0,45-0,4)]}=
=12,25-1,2x[11+1,1x(6,5+2x0,05)]=
=12,25-1,2x[11+1,1x(6,5+0,1)]=
=12,25-1,2x(11+1,1x6,6)=
=12,25-1,2x(11+7,26)=
=12,25-1,2x18,26=
=12,25-21,912=
=-9,662
e) [0,8+4x(o,34x10+1,2:2)]:0,168=
=[0,8+4x(3,4+0,6)]:0,168=
=(0,8+4x4):0,168=
=(0,8+16):0,168=
=16,8:0,168=
=100